∆ABC is a triangle , right angled at C. If AB = 13 cm , AC = 12 cm , find BC.
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In △ABC,
⇒ ∠B=90
o
[ Given ]
⇒ AB=12cm and AC=13cm [ Given ]
Here, O is center of a circle and x is a radius.
⇒ (AC)
2
=(AB)
2
+(BC)
2
[ By Pythagoras theorem ]
⇒ (13)
2
=(12)
2
+(BC)
2
⇒ 169=144+(BC)
2
⇒ (BC)
2
=25
∴ BC=5cm
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