Question

ABC is a triangle, right-angled at C. If AB = 15 cm and AC = 12 cm, then BC = ____ *​

Answer 1

Answer:

$\: \: \: \: \: \: \: \: \: \: \:$

Putting all known values in the eqⁿ :

\:

➝ 27.77 = 22.22 + a(5)

\:

➝ 5a = 27.77 - 22.22

\:

➝ 5a = 5.55

\:

➝ a = 5.55/5

\:

⚝ After cancelling 5.55 with 5, we get :

\:

➝ a = 1.11

\:

Therefore, acceleration (a) of a car is 1.11 m/s².

thankss !!!!

Answer 2

Step-by-step explanation:

hlo mate here's your answer

C3cm

Using Pythagoras theorem in △ABC

(AB) 2

(BC) 2

(AC) 2

(15) 2

(8) 2

(AC) 2

⇒

(AC) 2

225+

64=

289

⇒

AC=

17cm

Now inradius

r=

s

Δ

where Δ is the area of triangle and s is semi perimeter.

Δ=

2

1

× 8× 15= 60

s=

2

8+15+17

=

2

40

= 20 ⇒ r=

s

Δ

=

2 0

6 0

= 3cm

i hope its help you mark as brainlist