Question

ABC is a triangle right angled at C. If AB = 25 cm and AC = 7 cm, find BC? ​

Answer 1

AB = 25 cm, AC = 7 cm and BC =?

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2625 = 49 + (BC)2

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2625 = 49 + (BC)2(BC)2 = 625 – 49

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2625 = 49 + (BC)2(BC)2 = 625 – 49(BC)2 = 576

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2625 = 49 + (BC)2(BC)2 = 625 – 49(BC)2 = 576BC = 24 cm

AB = 25 cm, AC = 7 cm and BC =?In triangle ACB, By Pythagoras theorem, (Hypotenuse)2 = (Perpendicular)2 + (Base)2(AB)2 = (AC)2 + (BC)2(25)2 = (7)2 + (BC)2625 = 49 + (BC)2(BC)2 = 625 – 49(BC)2 = 576BC = 24 cmThus, BC is equal to 24cm

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