Question

ABC is a triangle,right angled at C if AB=25Cm,AC=7Cm,findBC​

Answer 1

$\pmb{\underline\blue{Given}}:-$

$⦿ \: \sf \: ABC \: is \: a \: \red △$

$⦿ \: \sf \: Right \: angled \: at \: \red{C}$

$\sf \: ▶AB = \red{ 25 cm}$

$\sf▶AC = \red{ 7 cm}$

$\pmb{\underline\blue{To \: Find}}:-$

$\sf▶BC = \: \red ?$

$\pmb{\underline\blue{Solution}}:-$

$\bf\underline{In \:△ABC,} \bf\underline{\:By \: Pythagoras \: theorem,}$

$\bf\red{AB² = AC² + BC²}$

$\bf\red{25² = 7² + BC²}$

$\bf\red{625 = 49 + BC²}$

$\bf\red{625 - 49 = BC²}$

$\bf\red{576 = BC^{2}}$

$\bf\red{\sqrt{576} = BC}$

${\underline{\boxed{\bf\red{BC = 24}}}}$

Answer 2

$\begin{gathered}\pmb{\underline\blue{\tt Given}}:- \\\end{gathered}$

$⦿ \: \sf \: ABC \: is \: a \: \red △⦿ABCisa△$

$⦿ \: \sf \: Right \: angled \: at \: \red{C}$

$\sf \: ▶AB = \red{ 25 cm}▶AB=25cm$

$\sf▶AC = \red{ 7 cm}▶AC=7cm$

$\begin{gathered}\pmb{\underline\blue{\tt To \: Find}}:- \\\end{gathered}$

$\sf▶BC = \: \red ?▶BC=?$

$\begin{gathered}\pmb{\underline\blue{\tt Solution}}:- \\\end{gathered}$

$\bf\underline{In \:△ABC,} \bf\underline{\:By \: Pythagoras \: theorem,}$

$\bf\red{AB² = AC² + BC²}$

$\bf\red{25² = 7² + BC²}$

$\bf\red{625 = 49 + BC²}$

$\bf\red{625 - 49 = BC²}$

$\bf\red{576 = BC^{2}}$

$\bf\red{\sqrt{576} = BC}$

$\begin{gathered}{\underline{\boxed{\bf\red{BC = 24}}}} \\ \\ \end{gathered}$