ABC is a triangle,right angled at C if AB = 25cm and AC= 15cm find BC
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Answered by
2
by P.G.T theorem
AB^2=BC^2+AC^2
25^2=BC^2+15^2
625=BC^2+225
625-225=BC^2
400=BC^2
√400=BC
20=BC
AB^2=BC^2+AC^2
25^2=BC^2+15^2
625=BC^2+225
625-225=BC^2
400=BC^2
√400=BC
20=BC
Answered by
1
In the triangle ABC right angled at C
AB=25cm
AC=15cm
According to Pythagoras theorem
We know that,
(Hypotenuse)²=(Base)²+(height)²
=> (Base)²=(hypotenuse)²- (height) ²
=> (BC)²= (25)²-(15)²
=> (BC)²=625-225
=> (BC)²= 400
=> (BC)² =(20)²
=>BC=20cm
Therefore BC is 20cm
AB=25cm
AC=15cm
According to Pythagoras theorem
We know that,
(Hypotenuse)²=(Base)²+(height)²
=> (Base)²=(hypotenuse)²- (height) ²
=> (BC)²= (25)²-(15)²
=> (BC)²=625-225
=> (BC)²= 400
=> (BC)² =(20)²
=>BC=20cm
Therefore BC is 20cm
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