ABC is a triangle through vertex A a line RQ is drawn parallel to side BC similarly PR and QP are the lines drawn through the vertex B and C parallel to AC and AB respectively to foam another triangle PQR. find the ratio of perimeter of Triangle ABC to that of triangle pqr
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Clearly, ABCQ and ARBC are parallelograms.
∴BC=AQ and BC=AR
⇒AQ=AR
⇒A is the mid-point of QR.
Similarly, B and C are the mid-points of PR and PQ respectively.
∴AB=½ PQ,BC= ½QR and CA½ PR
⇒PQ=2AB,QR=2BC and PR=2CA
⇒PQ+QR+RP=2(AB+BC+CA)
⇒ Perimeter of ΔPQR=2 (Perimeter of ΔABC)
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