Question

ABC is a triangle where AB=50cm BC=30cm AC=42cm .find the area of the triangle giving the answer to the nearest square centimeters
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Answer 1

Answer:

We have to use the heron's formula. Lets first find the semi perimeter (s).

s = (AB+BC+CA)÷2

s = (50+30+42)÷2

s = 61 cm.

Now, area A will be:

$A= \sqrt{s(s-a)(s-b)(s-c)$

$A= \sqrt{61(61-50)(61-30)(61-42)$

$A= \sqrt{61(11)(31)(19)$

$A= \sqrt{395219}$

$A=628.66 cm^{2}$

Thus, the answer is nearly 628.66 cm².

HOPE THIS HELPS :D