Question

ABC is a triangle whose AB=AC, P is any point in ABC, PAC is 20,ACP is 10,PAB is 60 then Find APB

Answer 1

Answer:

Given: AB=AC,

P is any point in ABC

LPAC= 20°

LACP= 10°

LPAB= 60°

To Find: LAPB

Solution:

80°+ 10° + x+ y =180° (ASP)

x+y = 90°

:. x= 90° – y ...(1)

10°+ x= y (Angles opposite to equal sides)

10°+ 90°– y =y (using (1))

100°= 2y

:. y= 50°

x= 90°–y (from (1))

x=90°–50°

:. x= 40°

L 1 + 20° + 10° = 180° (ASP)

:. L 1 = 150°

L 3 + L 2 + x = 180° (ASP)

L 3 = 140° – L 2 ...(2)

L APB = 360° – L1 – L2

= 360° – 150° – L2

= 110° – L2