ABC is a triangle with _A=64". The bisectors of B and C meet at a point
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Step-by-step explanation:
In △BOC,
∠BOC+∠OBC+∠OCB=180 (OB and OC bisect ∠B and ∠C respectively)
∠BOC+
2
1
∠B+
2
1
∠C=180
∠BOC=180−
2
1
(∠B+∠C)
∠BOC=180−
2
1
(180−∠A)
∠BOC=180−
2
1
(180−70)
∠BOC=180−90+35
∠BOC=125
∘
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