Question

ABC is a triangle with BC=12cmand Aac=8cmAX and BY are the perpendicular on BC and AC.if Ax=7cmfind BY
​

Answer 1

Answer:

this is your Answer hope it helps you

Step-by-step explanation:

From the fig:

AB=AC; B=C

BC=BP+PC=65 ...(1)

and PD=24; PE=36

In △PBD

BP=

sinB

PD

=

sinB

24

....(2)

In △PCE

PC=

sinC

PE

=

sinB

36

....(3)

From (2) & (3), we get BP=

3

2PC

....(4)

from (1) & (4),

BP=39 and PC=26

From (2), sinB=

39

24

=

13

12

⇒cosB=

13

5

∵A=π−B−C=π−2B

⇒sinA=sin2B=2sinBcosB=

169

120

using sine rule in ΔABC:

AB=AC=

sinA

BCsinB

=

sin2B

65sinB

=

2cosB

65

=

2

169

Therefore, △=

2

(AB)(AC)sinA

=2535

solution