ABC is a triangle with BD and CE are two medians BD =CE prove that AB =AC
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BD=CE (given)
BC=BC (common)
∠BEC = ∠ BDC (both are of 90 degree as BD and CE are medians)
by rhs rule
Δ BEC ≅Δ BDC
by CPCT
∠EBC=∠DCB
therefore ∠ABC=∠ACB
then AB=AC (sides opposite to equal angles are equal)
hence proved!
Step-by-step explanation:
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