Question

ABC is a triangle with D As mid point of AB . DE is perpendicular to AC and DF . BC . also DE = DF . prove that ∆ ABC is an isosceles ∆ >.​

Answer 1

Step-by-step explanation:

if we prove triangle AED congruent to triangle FDB by SSA test and the we prove triangle CED congruent to triangle CFD we get that ABC is an iscoscel triangle