Question

ABC is a triangle with D as midpoint of BC, DE is perpendicular to AB and DF is perpendicular to
AC. Also, DE = DF. Prove that ∆ ABC is an isosceles triangle.

Answer 1

Answer:

If ABC is a triangle and D is a midpoint of BC, and the perpendiculars from D to AB and AC are equal, how do you prove that the triangle is isosceles? ... Hence the triangles are congurent by RHS condition. Thus angles B and C are equal by c.p.c.t. thus AB = AC ( sides oppposite to equal angles of a triangle are equal).

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