Question

ABC is aequilateral triangle whose side is 10 cm each.three circles centering with A B and C with radius 5 cm find the area of middle remaing part

Answer 1

There are three parts of circles
area of triangle is a²√3/4=25√3cm²
there are three circles of equal area
area=58.57cm²
area of each part of circles in the triangle is=60/360×58.57×3=29.29cm² app.
remaining area=25√3-29.29=14.011cm²
Please mark it as brainliest