ABC is an acute angled triangle inscribed in a circle of radius 5cm and center at oO the sine of angleA is equalto 3/5 then calculate length of BC
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Given:
ABC is an acute angled triangle inscribed in a circle of radius 5cm and center at oO the sine of angleA is equalto 3/5
To find:
Calculate length of BC
Solution:
From given, we have,
ABC is an acute-angled triangle inscribed in a circle of radius 5cm and centre at oO the sine of angle A is equal to 3/5
Consider the attached figure while going through the following steps.
BC = 2a = 2R sin A
= 2 × 5 × 3/5
= 6 cm
Therefore, the length of BC is 6 cm
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