ABC is an equilateral traingle of side 2 a. find ech of its altitude
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Given: ABC is an equilateral triangle ∴ AB = AC = BC = 2a And let AD is an altitude on BC. Therefore, BD = 1/2 x BC = a Now, In ∆ADB, using Pythagoras theorem, we have (Perpendicular)2 + (Base)2 = (Hypotenuse)2 ⇒ (AD)2 + (BD)2 = (AB)2 ⇒ (AD)2 + (a)2 = (2a)2 ⇒ (AD)2 = 4a2 – a2 ⇒ (AD)2 = 3a2 ⇒ AD = a√3 unitsRead more on Sarthaks.com - https://www.sarthaks.com/931403/abc-is-an-equilateral-triangle-of-side-2a-units-find-each-of-its-altitudes
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