Question

Abc is an equilateral traingle the co ordinates of b and c are(3,0)and (-3,0) find.The co ordinates of vector

Answer 1

Answer:

Step-by-step explanation:

Suppose the coordinates of a is (x,y);

Given that b (3,0) and c (-3,0)

Using the distance formula;

ab = ac

$\sqrt{[(x-3)^2+ (y-0)^{2} } ]} = \sqrt{[(x+3)^{2}+(y-0)^{2}  ]}$;

by solving this we get x = -1 and y = 0 both are the coordinates of a

Answer 2

Answer:

(0 , 3√3)

Step-by-step explanation:

Given Abc is an equilateral triangle the co ordinates of b and c are(3,0)and (-3,0) find.The co ordinates of vector

The coordinates are given by (3,0) and (-3, 0)

Ad is perpendicular to BC and DB = CD = 3 units

Since the triangle is equilateral AB = BC = CA = 6 units

From triangle ADB,

            AB² = DB² + AD²

             AD² = 36 - 9 = 27

            AD = 3√3 units

Coordinates of A are (0, 3√3)