Question

Abc is an equilateral triangle, AD and BE are perpendicular to BC and AC respectively. Prove that :
i) AD =BE
ii)BD =CE​

Answer 1

Answer:

In △ ABC,

AB = BC = CA,

AD ⊥ BC, BE ⊥ AC,

Proof: In △ ADC and △ BEC

∠ADC = ∠BEC (each 90°)

∠ACD = ∠BCE (common)

and AC = BC (Sides of an equilateral triangle)

∴ △ ADC ≅ △ BEC (A.A.S. Axiom)

Hence, (i) AD = BE (c.p.c.t)

And (ii) BD = CE (c.p.c.t)

Hence proved.