Question

ABC is an equilateral triangle. Charges +q are placed at each corner as shown as fig. The electric intensity at centre O will be
(a) $\frac{1}{4\pi\epsilon_{0}}\frac{q}{r}$
(b) $\frac{1}{4\pi\epsilon_{0}}\frac{q}{r^{2}}$
(c) $\frac{1}{4\pi\epsilon_{0}}\frac{3q}{r^{2}}$
(d) zero

Answer 1

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Answer 2

Answer:

$\scriptsize\mathtt \pink{=\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1}}{r_{1 p }^{2}} \hat{ r }_{1 P }+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{2}}{r_{2 P }^{2}} \hat{ r }_{2 P }+\ldots .+\frac{1}{4 \pi \varepsilon_{0}} \frac{q_{n}}{r_{n P }^{2}} \hat{ r }_{n P }}$