Question

∆ ABC is an equilateral triangle. D is any point on BC. Another equilateral ∆ is constructed outside the ∆. AD and CE are joined. Show that AD = CE . just say how to procede

Answer 1

Answer:

See,

first , we have to show AD=CE.

so, D is the height of side of BE

And we all know that, In equilateral , sides are equal

hence, AD =CE.

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