Question

 ABC is an equilateral triangle. If AB = 30 cm, then find the area of  ABC using Heron’s formula. please give me a answer​

Answer 1

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Given that △ABC is an equilateral triangle it means all sides are equal

BC = CA = AB = 30 cm

⇒ s = (a + b + c)/2

⇒ s = 90/2

⇒ s = 45

Using heron's formula

$\sqrt{s(s - a)(s - b)(s - c)}$

Therefore,

= √(45 × (45 - 30) × (45-30) × (45 - 30))

= √(45 × 15 × 15 × 15)

= 225√3

Hence, area of triangle = 225√3

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Answer 2

Step-by-step explanation:

Given that △ABC is an equilateral triangle it means all sides are equal

BC = CA = AB = 30 cm

⇒ s = (a + b + c)/2

⇒ s = 90/2

⇒ s = 45

Using heron's formula

\sqrt{s(s - a)(s - b)(s - c)}

s(s−a)(s−b)(s−c)

Therefore,

= √(45 × (45 - 30) × (45-30) × (45 - 30))

= √(45 × 15 × 15 × 15)

= 225√3

Hence, area of triangle = 225√3