ABC is an equilateral triangle of each side 5 cm . Two charges of ±503×10−3μC are placed at B and A respectively . Find the magnitude of resultant field at C .
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Answer:6×10^4NC^-1
parallel to AB from + charge to - charge
Explanation:
The point C lies on equatorial line of electric dipole formed by charges
+_50/3×10^-3
placed at A & B respecitively.
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