ABC is an equilateral triangle of side 0.1m .Point charges of +3nc and -3nc are placed at the corners A and B respectively. Calculate the resultant electric intensity at C.
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As the point charges are oppositely charged, the electric intensity at point c due to both the charges will be in opposite direction and the angle between them will be 120°.
Now, as the angle between them is 120° the magnitude of electric field will be equal to electric field due to any of the charge.
E = kq/r²
= 9 × 10⁹ × 3 × 10⁻⁹ / 0.1 × 0.1
= 27× 10²
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