Question

ABC is an equilateral triangle of side 10 metre and D is the midpoint of BC charges of + hundred hundred and + 75 microcoulomb are placed at a b c and d respectively​

Answer 1

Answer:At The Point A 

Net field along x - axis 

E(x) = E(B) cos 60  + E(c) cos 60 

E(y) = E(D) + E(B) sin 60  - E(c) sin 60

Given that , a = 10 m 

Q(A) = + 1 μC

Q(B) = 100 μC

Q(c)  =  -100 μC

Q(D) = 75 μC 

k = 9 x 10⁹ N M ²C⁻²

Electric field ( magnitude)  are 

E(A) = 9000N/C

E(B) = 9000N/C

E(D) = 9000N/C

So , E(x)  = 9000 cos  60  + 9000 cos 60  

= [9000 x (1/2) ]x 2 = 9000N/C

E(y) =  9000 + 9000 sin 60 -  9000 sin 60 

= 9000N/C

So , net field of point A 

= 9000√2

E(n) = 12727.9N/C

So , Net force acting on point charger of (+1μC) is Given By

F = q E(n) 

 

  =(1 x 10⁻⁶) 12727.9 

F = 12.73 x 10⁻³N

Read more on Brainly.in - https://brainly.in/question/1359270#readmore

Explanation: