abc is an equilateral triangle of side 12 cm inscribed in a circle find the radius of the circle
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⇒( 1/2× AB × OR) + (1/2× BC × OP) + (1/2× AC × OQ) = √3/4× (side)2. Hence, the radius of the inscribed circle is 3.46 cm.
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Step-by-step explanation:
- ( 1/2× AB × OR) + (1/2× BC × OP) + (1/2× AC × OQ)
- = √3/4× (side)2.
- Hence, the radius of the inscribed circle is 3.46 cm.
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