Question

ABC is an equilateral triangle of side 2a. find each of its altitudes.​

Answer 1

It is simple yaar.

$area \: of \: triangle \\ = > \frac{1}{2} \times base \times height$

$area \: of \: equilateral \: triangle \\ = > \frac{ \sqrt{3} }{4} {s}^{2}$

$equating \: \\ = > \frac{ \sqrt{3} }{4}( {2a)}^{2} = \frac{1}{2}(2a)(height)$

$= > { \sqrt{3a} }^{2} = a(height)$

$height = a \sqrt{3}$