Question

Abc is an equilateral triangle of side 30m. a cow is tied at vertex a by means of 10m long rope. what is the area the cow can graze in?​

Answer 1

Step-by-step explanation:

area of a sector

here the angle will be 60 and radius is 10m

so area of the sector =(¤/360)*πr^2

=(60/360)*(22/7)*10*10

=1/6*22/7*100=52.38m^2

Answer 2

Answer:

ABC is equilateral triangle so all side equal

a cow tied at vertex rope =10m

each side 30 m

when we tied at vertex i.e I tied at point of A in equilateral triangle

then we find area cow can graze in ?

height of rope 10 m

area of equilateral triangle = ✓3/4× a^ 2

= ✓3/4 ×(10)^2

= 43.30 m