Question

ABC is an equilateral triangle of side 4V3 cm. P, Q and R are mid-points of AB, CA and BC
respectively. The area of triangle PQR is (in cm?​

Answer 1

Answer:

Area of triangle ABC=v3a2/4

=v3x(4 v3)^2/4=v3 x 16x3/4

= .12 v3cm2

Step-by-step explanation:

Area of the triangle is 1/4 of

area of triangle ABC

I/4 of 12v 3=3v3 cm2

Answer 2

Let DEF be the midpoints of sides of a triangle ABC( with D on BC, E on AB and F on AC ). Now, considering triangles AEF and ABC, angles EAF = BAC and AE / AB = 1/2 and AF/AC = 1/2. ... The triangle formed by joining the mid-points of the equilateral triangle is also an equilateral triangle

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