Math, asked by om3393, 1 year ago

ABC is an equilateral triangle of side 6 cm. If a circle of radius 1 cm is moving inside and along the side of the triangle, then the locus of the centre of the circle is an equilateral triangle of side is:

( 3 + \sqrt{3}  )\: cm
(6 - 2 \sqrt{3} ) \: cm
4cm
5cm

Answers

Answered by sankar92
5

6 - 2 \sqrt{ 3}

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