ABC is an equilateral triangle of side 'a'. Then AB.BC + BC. CA+CA.AB =
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Answer:
Step-by-step explanation:
1st way ABC is an equilateral triangle so AB=BC=AC = X(let it be x )
AB.BC + BC. CA+CA.AB =
x*x+x*x+x*x =
x^2 + x^2 + x^2 = 3x^2
or, 3(AB)^2 OR 3(BC)^2 OR 3(CA)^2
2nd way
AB.BC + BC. CA+CA.AB = (by taking them as variables)
ACB^2 + BAC^2 + BCA^2 =
B(ACB + AC^2 + CA^2) =
B(C(AB + AC + A^2)) =
B(C(A(B + C + A))) =
B * C * A * (A+B+C)
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