Question

ABC is an equilateral triangle. P is a point on AB and Q is a point on AB produced. Prove that, :-
CP < AB
CQ > AB

Who will give me correct answer with no mistakes, I will mark him branliest​

Answer 1

Answer:

REF. Image.

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ] [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c [common]

and BC=BC [common]

∴ΔBCP≃ΔBCQ [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]