Math, asked by asthamahaa, 1 month ago

ABC is an equilateral triangle. P is a point on AB and Q is a point on AB produced. Prove that, :-
CP < AB
CQ > AB

Who will give me correct answer with no mistakes, I will mark him branliest​

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Answers

Answered by yeshirai
0

Answer:

REF. Image.

Given AB=AC

and AP=AQ

Thus

AB-AP=AC-AQ

[BP=CA ] [from figure ]

now InΔBCP & ΔBCQ

BP = CQ

∠c=∠c [common]

and BC=BC [common]

∴ΔBCP≃ΔBCQ [SAS congruency]

now

[BQ=CP] [corresponding parts of congruent triangles]

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