Question

∆ABC is an equilateral triangle. Point P is on base BC such that

PC = 1/3BC. If AB = 12 cm, find AP.​

Answer 1

Answer:

PC=1/3 BC

so,

BC=3 PC

as we know its an equilateral triangle so,

AB=BC=AC=12

12=3PC

PC=4

so,

AP=AC-PC

=12-4

Ap=8cm