ABC is an equilateral triangle. Seg AB is perpendicular to side BC. O is the orthocentre if ABC. If l (AO) = 4.2 cm, what is l(AM) ?
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ABC is an equilateral triangle. Seg AB is perpendicular to side BC. O is the orthocentre if ABC. If l (AO) = 4.2 cm, what is l(AM) ?
Step-by-step explanation:
We know that for an equilateral triangle,orthocentre l and centroid lie at the same point.Also altitude and the median are equal.
Therefore, point O divides AM into 2:1
Therefore, 2/3 *l = 4.2
l = 4.2*3/2
= 2.1*3
=6.3
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Answer:
(3) A ABC is an equilateral triangle. Seg AM is perpendicular to side BC. O is the
(A) 2.1 cm (B) 4.2 cm (C) 6.3 cm (D) Cannot say exactly
orthocentre of A ABC. If 1(AO) = 4.2 cm, what is /(AM)?
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