ABC is an equilateral triangle. Taking BC as
the base, construct a right angled triangle
equal in area to equilateral triangle ABC.
(The side used as the base should not be one
arm of the right angle).
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Step-by-step explanation:
AB² + BC² = AC² ..... Pythagoras theorem ...(1)
ar (PAB) =√3/4×AB²........ equilateral ∆s
ar ( QBC) = √3/4×BC²........
ar (RAC) =√3/4 ×AC².......
Multiply (1) by √3/4 on both sides
√3/4AB² + √3/4BC² = √3/4AC²
.: ar ∆PAB + ar ∆QBC = ar ∆RAC
HENCE PROVED......
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