ABC is an equilateral triangle the coordinates of vertices B and C are (3,0) and (- 3,0) respectively find the coordinates vertex A
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Answered by
59
here we have to find the coordinates vertex of A. since A is in the Y axis. the x coordinate is 0. so, vertex of A is (0,y).now we have find the value of y. given the triangle is equilateral. hence
distance of BC= distance of AB
=> (3--3)^2+(0-0)^2=(3-0)^2+(0-y)^2
=> 36= 9+ y^2
=> y^2= 25
=> y =5
hence coordinate vertex of A is (0,5)
hope this helps you.
distance of BC= distance of AB
=> (3--3)^2+(0-0)^2=(3-0)^2+(0-y)^2
=> 36= 9+ y^2
=> y^2= 25
=> y =5
hence coordinate vertex of A is (0,5)
hope this helps you.
Answered by
4
Answer:
anser is = (0,5)
Step-by-step explanation:
as the point lies on y axis
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