Question

ABC is an equilateral triangle with each side of length 10 cm in ∆BCD angle D is 90° and CD= 6 cm find the area of the shaded region give your answer correct to one decimal place​

Answer 1

Given side of Equilateral ∆ = √3/4a²

a= 10 cm

Area = √3/4 ×10 ×10 cm2

Area = 100√3/4 cm² = 43.3

Now In ∆ BDC

/_ D = 90°

BC² = BD² + CD²

100 = 36 + CD²

CD = √64 = 8

Area of ∆ BDC =

1/2 * b * h

1/2 * 6 * 8 = 24

Area of shaded region = 43.3 - 24 =19 .3 cm²

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Answer 2

Step-by-step explanation:

Hi oppa

Your answer is in the attachment

Hope it helps ...

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