Question

∆ABC is an equilateral triangle with each side of length 2p. if AD perpendicular to BC then find the length of AD​

Answer 1

Answer:

3p

Step-by-step explanation:

You can use the pythagoras theorem to find this out

Pythagoras theorem says a²+b²=c² so,

a²+b²=c²

x²+1²=2²

x²=2²-1²

x²=4-1

x²=3p

I have taken triangle ADB, so considering AD as a bisector BC becomes the Half that is BD which we want for the traingle. I used the pythagoras theorem and just transposed the values, to get the desired answer

HOPE IT HELPS YOU WELL!

Answer 2

Given : ∆ABC is an equilateral triangle with each side of length 2p. AD perpendicular to BC.

To find : length of AD

Solution :

In equilateral triangle, all the sides are same and the angles are 60. Height of equilateral triangle is given by :

$\frac{ \sqrt{3} }{2} \times a$

where a is the side length of the equilateral triangle.

Here, a = 2p

Therefore, height is =

$\frac{ \sqrt{3} }{2} \times 2p$

=

$\sqrt{3} p$

Height =

$\sqrt{3} p$