Abc is an equilateral triangle with perimeter,60 cm s and r are the points on side ac and ab p and q are points on side bc srparallel bc sp parallel bc, cd parallel to er so+
Answers
Length of PQ. = 10 cm
Step-by-step explanation:
∆ABC is an equilateral ∆ with perimeter 60 cm.
=> Side of ∆ABC = 60/3 = 20 cm
SR//BC
=> ΔASR ≈ ΔABC
=> ΔASR is equilateral triangle
Let say SR = x cm
=> AS = AR = SR = x cm
=> BS = 20 - x cm
CR = 20 - x cm
as SP//AC, RQ//AB
=> ΔBSP ≈ ΔBAC & ΔCRQ ≈ ΔCAB
=> ΔBSP & ΔCRQ are equilateral triangle
=> SP = BS = 20 - x cm
QR = CR = 20 - x cm
SR + SP + RQ = 25 cm
=> x + 20-x + 20 -x = 25
=> x = 15 cm
BP + PQ + QC = BC
=> BS + PQ + CR = 20
=> 20 -x + PQ + 20 - x = 20
=> PQ = 2x - 20
x = 15
=> PQ = 2 * 15 - 20
=> PQ = 10
length of PQ. = 10 cm
Learn more:
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https://brainly.in/question/14398147
Answer:
Step-by-step explanation:
Length of PQ. = 10 cm
Step-by-step explanation:
∆ABC is an equilateral ∆ with perimeter 60 cm.
=> Side of ∆ABC = 60/3 = 20 cm
SR//BC
=> ΔASR ≈ ΔABC
=> ΔASR is equilateral triangle
Let say SR = x cm
=> AS = AR = SR = x cm
=> BS = 20 - x cm
CR = 20 - x cm
as SP//AC, RQ//AB
=> ΔBSP ≈ ΔBAC & ΔCRQ ≈ ΔCAB
=> ΔBSP & ΔCRQ are equilateral triangle
=> SP = BS = 20 - x cm
QR = CR = 20 - x cm
SR + SP + RQ = 25 cm
=> x + 20-x + 20 -x = 25
=> x = 15 cm
BP + PQ + QC = BC
=> BS + PQ + CR = 20
=> 20 -x + PQ + 20 - x = 20
=> PQ = 2x - 20
x = 15
=> PQ = 2 * 15 - 20
=> PQ = 10
length of PQ. = 10 cm
Learn more:
In figure 5.22, ABCD is a parallelogram,P and Q are midpoints of ...
brainly.in/question/4591045
∆ABC is an equilateral ∆ with perimeter 60 cm
brainly.in/question/14398147