ΔABC is an equilateral Tringle. AD bisects ∠BAC. Show that ΔABC≅ΔACD
Answers
Answered by
4
Heya Mate !!!
Here's Your Answer ;-
========================
Step by Step Explanation ;-
========================
In ∆ABD and ∆ACD :-
AB = AC ( Equilateral ∆'s of same side measure )
AD = AD ( Common )
BD = DC ( Because Ad bisect BC )
Hence , ∆ABD ≈ ∆ACD by SSS congruent property.
Here's Your Answer ;-
========================
Step by Step Explanation ;-
========================
In ∆ABD and ∆ACD :-
AB = AC ( Equilateral ∆'s of same side measure )
AD = AD ( Common )
BD = DC ( Because Ad bisect BC )
Hence , ∆ABD ≈ ∆ACD by SSS congruent property.
Attachments:
Similar questions