ΔABC is an equilateral Tringle. AD bisects ∠BAC. Show that ΔABC≅ΔACD
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Heya Mate !!!
Here's Your Answer ;-
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Step by Step Explanation ;-
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In ∆ABD and ∆ACD :-
AB = AC ( Equilateral ∆'s of same side measure )
AD = AD ( Common )
BD = DC ( Because Ad bisect BC )
Hence , ∆ABD ≈ ∆ACD by SSS congruent property.
Here's Your Answer ;-
========================
Step by Step Explanation ;-
========================
In ∆ABD and ∆ACD :-
AB = AC ( Equilateral ∆'s of same side measure )
AD = AD ( Common )
BD = DC ( Because Ad bisect BC )
Hence , ∆ABD ≈ ∆ACD by SSS congruent property.
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