Math, asked by drsunita78, 1 year ago

ΔABC is an equilateral Tringle. AD bisects ∠BAC. Show that ΔABC≅ΔACD

Answers

Answered by Anonymous
4
Heya Mate !!!

Here's Your Answer ;-

========================
Step by Step Explanation ;-
========================

In ∆ABD and ∆ACD :-

AB = AC ( Equilateral ∆'s of same side measure )

AD = AD ( Common )

BD = DC ( Because Ad bisect BC )

Hence , ∆ABD ≈ ∆ACD by SSS congruent property.




Attachments:
Similar questions
Math, 1 year ago