∆ABC is an equlateral traingle in which AB=(3x+1)cm, BC=(2x+3y+5)cm and AC=(x+9y+6)cm. find the value of x and y
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AB = BC = AC
AB = BC
3x + 1 = 2x + 3y + 5
3x - 2x - 3y = 5 - 1
x - 3 y = 4 → 1
BC = AC
2x + 3y + 5 = x + 9y + 6
2x + 3y - x - 9y = 6 - 5
x - 6y = 1 → 2
Subtracting 1 from 2
x - 6y - x + 3y = 1 - 4 = -3
-3y = -3
y = 1
Substituting y = 1 in 1
x = 7
Side = 22 cm
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AB = BC
3x + 1 = 2x + 3y + 5
3x - 2x - 3y = 5 - 1
x - 3 y = 4 → 1
BC = AC
2x + 3y + 5 = x + 9y + 6
2x + 3y - x - 9y = 6 - 5
x - 6y = 1 → 2
Subtracting 1 from 2
x - 6y - x + 3y = 1 - 4 = -3
-3y = -3
y = 1
Substituting y = 1 in 1
x = 7
Side = 22 cm
hope it helps you. . . . . . mark as a brainlist. . . . . . follow me. . . .
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