Question

ABC is an isoceles triagle with AB=AC. Draw AP perpendicular BC to show that angle B= angle C

Answer 1

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Here's your answer....
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in ∆ABP and ∆ACP

AB = AC
angle APB = angle APC [ AP perpendicular BC]
AP is common

so, ∆ABP congruent to ∆ACP [ by RHS congruence rule]

so, angle B = angle C [corresponding angles of congruent triangle]

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