Question

ABC is an isoceles triangle in which AB=AC.ADbisects exterior angle PAC and CD parallel to AB.Show that1)/_DAC=/-BCA2)ABCD IS A llgm

Answer 1

$\textbf{ \underline{ \huge{ Hello Mate! }}}$

Given : AB = AC, AD bisects < PAC and CD || AB.

To Prove : < DAC = < BCA and ABCD is ||gm.

Concepts used :

1. When alternate angles formed by transversal intersecting two distinct lines are equal then two lines are said to be parallel.

2. If two pairs of quadrilateral are parallel then quadrilateral is a parallelogram.

Please refer to attatchment for proof.

$\textbf{ \large{ Q.E.D }}$

$\textbf{ Have great future ahead! }$