Question

ABC is an isoceles triangle in which AB =AC and AD is the bisector of angle A.

a. is ABD = ACD?
B. is angle ADB =90 degree?
c. IS Dv5he mid-point of BC?
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Answer 1

Hope these helps you....

Answer 2

Answer:

In tri.ABD and tri.ACD ,

>> AB = AC

>> angle ABD = angle ACD [ angles opposite to equal sides are equal ]

>> AD = AD [common ]

>> tri.ABD = tri.ACD [SAS]

>> angle 1 = angle 2 [CPCT]........{1}

>> BD = CD [CPCT].......{2}

we have been proved that angle 1 is equal to angle 2 but

angle 1 + angle2 = 180° [ supplementary angles ]

so, angle 1 + angle 1 = 180° [angle 1 = angle 2]

2(angle1)=180°

angle 1 = 180/2

angle1= 90°

angle ADB=90°........{3}

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