Question

ABC is an isoceles triangle in which BE And CF are equal sides AC and AB respectively. Show that these altitudes are equal ​

Answer 1

Answer:

since the sides ab and base ac are equal to 'be' and 'cf' ...this implies that the third side is also equal.....proving that the triangles are congruent

this mean that the altitudes of the triangles are also equal ( by cpct)  

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

given = ABC is an isosceles triangle in which altitude BE and CF are drawn to sides AC and AB respectively.

To prove : BE =CF .

Proof ABC is an isosceles triangle.

AB = AC

Angle ABC =angle ACB .....(1)

angles opposite to equal sides of a triangle are equal. In triangle BEC and triangle CFB ,

angle BEC =angle CFB [ each =90⁰]

BC = CB [ common ]

angle ECB =angle FBC , from (1)

triangle BEC congruent to triangle CFB [BY AAS rule]

therefore, BE =CF . ( C.P.C.T .)