ABC is an isoceles triangle with AB=AC and D is mid point on AC such that BC*BC = Ac * CD PROVE THAT BD=BC
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THEREFORE BC×BC=AC×CD
=> BC×BC=AB×CD
BC²=AB×CD
AB=CD-BC²
AB×CD=BC²
THEREFORE PUTTING ON (1) BC²=BC²
√AB×CD=BC
BC=√AB×CD
HENCE THAT IS NOT PROVED BD=BC
THANG YOU
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