ABC is an isoceles triangle with ab is equal to AC and CP parallel to ba and it is a bisector of exterior angle C A D of triangle ABC prove that p a c angle is equal to angle BCA and prove that ABCP is a parallelogram
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First of all you should draw the figure of this question then you find angle Pac is equal to angle bca by alternative angle thereon ok
Then there Is one more thereon as i stiudyed if one sied of quardileateral is equal and parallel to another side then it will be a parallelogram so if u understood pls tell me quickly
magiccreator100:
Sorry can't understand
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