ABC is an isoscales triangle right angled at C .prove that AB square= 2 AC square
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Given data :
Δ ABC is a right Δ and also isosceles triangle.,
To prove:
Step 1:
Proof:
Here,
Hypotenuse = AB
Also, as it is given that, ΔABC is isosceles,
Step 2:
AC = BC [equal sides of isosceles Δ]
Using Pythagoras theorem,
Step 3:
In Δ ABC, we have ;
[AC = BC]
\mathrm{AB}^{2}=2 \mathrm{AC}^{2}
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