Question

ABC is an isosceles , AB=AC.P is a point inside triangle ABC such that angle BCP=30° ,angle APB=150°and angle CAP =39°

Answer 1

ABC is an isosceles , AB=AC.

Step-by-step explanation:

• There are given three angle such as
• APC = 39
• APB = 150
• BPC = 30
• ABC = X +39, Y+Z, W+30 Y+Z = W+30
• The P point will be at 360
• The total of these three interior angles are 180
• t is eliminated from here.
• t = 210 - s
• Triangle BPC has some interior angle such as z,s and 30 which is added into 180
• s = 150-z where s is eliminated
• Now t is equal to z + 60
• Isosceles angle are y +z w + 30
• so that y = w-z+30
• y = 111-2z
• The interior angles of ABP  is added with 180
• x+39+111-2z+z+81-z+30 = 180
• Now it is given again x = 2z-81
• If the angle of BAP is +z that must be greater than the 40.5
• If the angle of ABP is +z then it must be around 55.5

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Answer 2

Answer:

Angle BAP=75

Step-by-step explanation:

Answer is in the attachment below.

All angles are found using angle sum property in the triangles.