Question

∆ABC is an isosceles ∆ inscribed in a circle with
AB = AC and BT is tangent at B and angle CBT=40°
then angle C will be:
al 40^°
b) 60°
c) 70°
d)80°​

Answer 1

Answer:

As tangents drawn from an external point to a circle are equal in length.

So, therefore, we get AP=AQ (tangents from A)

BP=BR (tangent from B)

CQ=CR (tangent from C)

It is given that ABC is an isosceler triangle with sides AB=AC

⇒AB−AP=AC−AP

⇒AB−AP=AC−AQ

⇒BR=CQ

⇒BR=CR

So, therefore, BR=CR that imples BC is bisected at the point of contact.

Answer 2

Answer:

According to question

Step-by-step explanation:

the angle C will be 60°