Question

ABC is an isosceles right angled triangle. Assuming AB=BC=x, find the value of each of the following trigonometric ratios: i) sin 45° ii) cos 45° iii) tan 45°​

Answer 1

Step-by-step explanation:

ABC is right angle triangle

right angle at B

AB = BC = x

AB = opposite side

BC = adjacent side

AC = hypotenuse

by Pythagoras theorem

${ac}^{2} = {ab}^{2} + {bc}^{2} \\ {ac}^{2} = {x}^{2} + {?}^{2} \\ {ac}^{2} = 2 {x}^{2} \\ ac = \sqrt{2 {x}^{2} } \\ ac = \sqrt{2} x$

hypotenuse AC = √2x

sin 45° = opp/hyp = x/√2x = 1/√2

cos 45° = adj/hyp = x/√2x = 1/√2

tan 45° = opp/adj = x/x = 1

hope you get your answer

Answer 2

Step-by-step explanation:

hope it helps.... ......